Answer Posted / rajesh paul

Actually this is a very obvious question from our curiosity...
Even I was also very much puzzled at one time with this question and after a long time of discussion with my frnds and some books I got it clear. The explanation is as follows--




consider the code segment given by Brian--


class MyStatic
{
public:
MyStatic() { cout << "MyStatic Class called." << endl; };
};

static MyStatic ms;

void main()
{
cout << "main called." << endl;
}

Output : =
MyStatic Class called.
main called.
---------------X---------------

This happens because at run-time the static members are loaded into the RAM automatically along with the main() function. Hence as the class 'MyStatic' is statically instantiated before main(), the constructor function is called before main() as because the object is static i.e. already loaded into RAM hence the constructor is executed. Thereafter the main() is executed.


So from this discussion we come to the conclusion that "It is OS that instructs the system loader to load the main() into RAM automatically at run-time but no other function is loaded into RAM until and unless the main() calls them". That's what I want to say...........................

Explain stl.

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totoo po ba ang manga aliens!

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To modify an, existing worksheet. What steps are involved for: 1. Inserting and deleting rows and columns. 2. Printing cell formulas 3Jld displayed values 3. Using the page setup command

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