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There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
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Answer Posted / ashish rawat
let the length of candle is – L
let ramesh light candles x hours ago
thinner one lasts = 4h
length burnt in one hour = L/4
length burnt in x hour = xL/4
remaining length = L-(xL/4) = (4-x)L/4
thicker one lasts = 6h
length burnt in one hour = L/6
length burnt in x hour = xL/6
remaining length = L-(xL/6) = (6-x)L/6
now according to conditions after x hours , thicker candle
length = 2*thinner candle length
(6-x)L/6 = 2* (4-x)L/4
(6-x) = 3*(4-x)
2x = 12-6 = 6
x = 3 hours
| Is This Answer Correct ? | 8 Yes | 3 No |
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