A man speaks the truth 3 out of 4 times. He throws a die
and reports it to be a 6. What is the probability of it
being a 6?

(a) 3/8
(b) 5/8
(c) 3/4
(d) None of the above

Answer Posted / hynynu

prob. of getting 6 in a die p(e1)=1/6
prob. of not getting 6 in a die p(e2)=1-(1/6)=5/6
prob. of the man getting 6 in a die and reporting it as 6
i.e. truth p(e/e1)=3/4
prob. of the man NOT getting 6 in a die and reporting it as
6 i.e. lying p(e/e2)=1-(3/4)=1/4

P= p(e1)p(e/e1)
------------------------
p(e1)p(e/e1)+p(e2)p(e/e2)

p= 1/6*3/4
--------------------
(1/6*3/4)+(5/6*1/4)

p= 3/8
Answer is (a)

Is This Answer Correct ?    7 Yes 1 No



Post New Answer       View All Answers


Please Help Members By Posting Answers For Below Questions

what is an active ? (UML)

1925


How to Insert Genomic DNA into yeast ?

1530


How to predict the function of a gene (product)?

1558


What is the input and outpit of a distance based algorithm?

1807


What two possibilities are there to describe how gene fragments may have evolved?

1726






How to identify common acc.numbers from among a set of files ?

2336


How to find coexpressed genes on NCBI GEO?

1675


Can independent origins be established for two families of transport systems having no sequence or motif similarities without three-dimensional structural data?

590


What are the current challenges in the Pharmaceutical and biotechnology sectors?

1747


What is computational biology?

567


What is the idea behind ?weighting? sequences in the package CLUSTAL W for multiple alignment? How are these weights calculated?

1540


Will the plant able to produce electricity when the soil is dried up

1198


How the Algorithm works?

1521


How do you customize database for blast?

609


Integrate 3x + 5 / (x3-x2-x+1)?

1753