Answer Posted / kartik sharma

In case of String s=new String("vali"); , a memory in the heap is allocated to the variable of the class String, and then the value is given to the variable s="vali". Using new operator , we can allocate the memory to the instance of the class.


But in String s="vali" , only the variable s is given the value as vali but there is no permanent memory given to the variable in heap.

Why do we use encapsulation in oops?

522

---

What is static modifier?

631

---

Can you inherit a private class?

631

---

class CTest { public: void someMethod() { int nCount = 0; cout << "This is some method --> " << nCount; } }; int main() { CTest *pctest; pctest->someMethod(); return 0; } It will executes the someMethod() and displays the value too. how is it possible with our creating memory for the class . i think iam not creating object for the class. Thanks in Advance... Prakash

1698

---

Is abstract thinking intelligence?

594

---

---

How can you overcome the diamond problem in inheritance?

768

---

Can we have inheritance without polymorphism?

613

---

What is cohesion in oop?

624

---

Why interface is used?

553

---

write string class as your own class in java without using any built-in function

1976

---

What is byval and byref? What are differences between them?

1689

---

IS IT NECESSARY TO INITIALIZE VARIABLE? WHAT IF THE INSTANCE VARIABLE IS DECLARED final ? IS IT NECESSARY TO INITIALIZE THE final VARIABLE AT THE TIME OF THEIR DECLARATION?

1581

---

Where You Can Use Interface in your Project

1427

---

What does and I oop and sksksk mean?

652

---

What is the highest level of cohesion?

579

---