You have two jars, 50 red marbles and 50 blue marbles. A jar
will be picked at random, and then a marble will be picked
from the jar. Placing all of the marbles in the jars, how
can you maximize the chances of a red marble being picked?
What are the exact odds of getting a red marble using your
scheme?
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Answer Posted / gregg
put 1 red marble in one jar and all the rest (99) in the
other.
This gives you 50% from the first jar (if they pick that
jar they will get red 100% of the time). For the other jar
the chances are 49/99 or 49.494949%. Divide that by 2 and
its 24.7474%. Total odds are 50% plus 24.7474% = 74.7474%
| Is This Answer Correct ? | 56 Yes | 4 No |
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