Answer Posted / sagar sapkota

A function is overloaded when same name is given to different function. However, the two functions with the same name will differ at least in one of the following.

a) The number of parameters
b) The data type of parameters
c) The order of appearance

These three together are referred to as the function signature.

For example if we have two functions :

void foo(int i,char a);
void boo(int j,char b);

Their signature is the same (int ,char) but a function

void moo(int i,int j) ; has a signature (int, int) which is different

While overloading a function, the return type of the functions need to be the same.

In general functions are overloaded when :

1. Functions differ in function signature.
2. Return type of the functions is the same.

Operator overloading allows existing C++ operators to be redefined so that they work on objects of user-defined classes. Overloaded operators are syntactic sugar for equivalent function calls. They form a pleasant facade that doesn't add anything fundamental to the language (but they can improve understandability and reduce maintenance costs).

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