Given a triangle ABC, how would you use only a compass and
straight edge to find a point P such that triangles ABP, ACP
and BCP have equal perimeters? (Assume that ABC is
constructed so that a solution does exist.)
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Answer Posted / koushik
The answer probably lies in finding the in-centre of the
traingle. Bisect all the angles of the triangles and the
point where these angle bisectors meet gives u the point P
| Is This Answer Correct ? | 6 Yes | 1 No |
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