The matrix of a (7,9)was given.The address of the first byte
of a (1,1)matrix=1258.It takes 4 bytes to store the
number,then calculate the address of the last byte of a
(5,8) matrix??
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Answer Posted / vijay
plz post clr question..?
The matrix of a (7,9)was given.The address of the first byte
of a (1,1)matrix=1258.It takes 4 bytes to store the
number,then calculate the address of the last byte of a
(5,8)element??
ans is 1433
In column address increments by (8x4+4)36=clmn-gap
In row address increments by 4=row-gap
So
add of (5,8) element (4 clmn-gaps & 7 row-gaps )
=1258+4x36+4x7=1430
add of last byte=[1430,1431,1432,1433]
ans 1433
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