Write a program that takes a 3 digit number n and finds out
whether
the number 2^n + 1 is prime, or if it is not prime find out its
factors.
Answer Posted / sreejesh1987
//Sorry, this code is wrong
//but'll be useful for some other logic
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n,x,flag=0,d;
clrscr();
printf("\tPRIME CHECK\n");
printf("Enter a 3digit no:");
scanf("%d",&n);
if((n/100>0)&&(n/100<10))
printf("\nNumber is of 3 Digits");
else
printf("\nNot a 3 digit number");
for(j=2;j<n,n%j!=0;j++)
if(n-1==j)
{
printf("\n\t%d is a prime",n);
flag=1;
d=n-1;
while(d%2==0)
d=d/2;
if(d==1)
printf("\nNumber%d is in 2^n+1 format",n);
}
if(!flag)
{
printf("\nNumber %d is not a prime",n);
printf("\nIts factors are:\n\t");
x=2;
while(n!=1)
{
while(n%x==0)
{
n=n/x;
printf("%d ",x);
}
x++;
}
}
getch();
}
Is This Answer Correct ? | 16 Yes | 6 No |
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