main()
{
char i=0;
for(;i>=0;i++) ;
printf("%d\n",i);
}
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Answer Posted / susie
Answer :
Behavior is implementation dependent.
Explanation:
The detail if the char is signed/unsigned by default
is implementation dependent. If the implementation treats
the char to be signed by default the program will print –128
and terminate. On the other hand if it considers char to be
unsigned by default, it goes to infinite loop.
Rule:
You can write programs that have implementation
dependent behavior. But dont write programs that depend on
such behavior.
| Is This Answer Correct ? | 5 Yes | 2 No |
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I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..
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