What is the output of the program given below

main()

{

signed char i=0;

for(;i>=0;i++) ;

printf("%d\n",i);

}

Answer Posted / susie

Answer :

-128

Explanation

Notice the semicolon at the end of the for loop. THe initial
value of the i is set to 0. The inner loop executes to
increment the value from 0 to 127 (the positive range of
char) and then it rotates to the negative value of -128. The
condition in the for loop fails and so comes out of the for
loop. It prints the current value of i that is -128.

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