A packet of 10 Kb is to be downloaded from a web server.
Find the time needed to download this packet using:
a) A dial up telephone connection at 28 Kbps
b) A cable modem at 28 Mbps.
Answer Posted / david tilley
The straight maths answer is: Ti = Fs/Sp
Where:
Ti...Time
Fs..FileSize
Sp..Speed
a) Ti = 10,000 / 28,000
= 357ms
b) Ti = 10,000/ 28,000,000
= 357uS
However.... In practice transfer times would be longer than
this depending on the overhead added to handle error
checking/recovery.
Is This Answer Correct ? | 30 Yes | 6 No |
Post New Answer View All Answers
How do I unblock a port?
Which layer is closer to the user?
What is a private ip address?
What is the use of internet addresses?
How do I find out what service is using a port?
Explain 3 way handshake and how it works?
How can I check if port 80 is open?
What does tcp/ip stand for?
What is the difference between host and ip address?
Does http request contain ip address?
What is my ip from command line?
Can ip addresses be shared?
What is unix port?
What is echo in networking?
What does round trip time mean?