a clock which gains uniformly was observed to be 5min
slow at 12 noon on monday. it was noticed 10 min fast at
6pm . on the next day .when did the watch show the correct
time (* PLEASE GIVE THE EXPLANATION*)
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Answer Posted / roy
10 pm on monday.
From 5 min slow to 10 min fast, the clock gained 15 mins
This it did in 30 hrs (12 noon to 12 noon plus 6 hrs next
day). so to gain 1 min it took 2 hrs (30/15). So to make up
the late timin of 5 mins (and thus to show the correct
timing) it will take 5*2=10 hrs. 12 noon to 10 hrs is 10pm.
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