A bus started from the bus stand at 8 Am and after staying
30 minutes at a destination return back to the bus stand.
The Destination is 27 miles from the bus stand . The Speed
of the bus is 18mph . In the return journey the bus travells
with 50% fast speed.At what time it is return to the bus
stand ?
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Answer Posted / praveen
Bus started at 8:00
it travelled with 18mph...
distance of destination is 27 miles...
we know velocity=(distance)/time
i.e., time=27/18hours=3/2hours=90 min...
i.e., the bus reached destination at 9:30
the bus stayed for 30 min...
so the bus started return journey at 10:00
now the bus returned with velocity 18 + (18/2)=27mph
the taken to the bus to travel = 27/27=1 hour = 60 min...
so bus would be returned on 11:00...
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