1)
int i=5;
j=i++ + i++ + i++;
printf("%d",j);This code gives the answer 15.But if we
replace the value of the j then anser is different?why?
2)int i=5;
printf("%d",i++ + i++ + i++);
this givs 18.
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Answer Posted / prasoon
both the codes possess undefined behaviour because the value
of i is changing more than once between two sequence points...
hence my answer is undefined behaviour
| Is This Answer Correct ? | 14 Yes | 6 No |
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