A man speaks the truth 3 out of 4 times. He throws a die
and reports it to be a 6. What is the probability of it
being a 6?
(a) 3/8
(b) 5/8
(c) 3/4
(d) None of the above
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Answer Posted / mohsin
P(it is six|reports six) = P(it is 6, reports six)/P(reports
six) = [3/4*1/6] / [(3/4*1/6) + (1/4*5/6*1/5)] = 3/4
(c)
| Is This Answer Correct ? | 20 Yes | 25 No |
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