Answer / susie

Answer :

1==1 is TRUE

Explanation:

When two strings are placed together (or separated by
white-space) they are concatenated (this is called as
"stringization" operation). So the string is as if it is
given as "%d==1 is %s". The conditional operator( ?: )
evaluates to "TRUE".

main(){ char a[100]; a[0]='a';a[1]]='b';a[2]='c';a[4]='d'; abc(a); } abc(char a[]){ a++; printf("%c",*a); a++; printf("%c",*a); }

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write a c program to Create a registration form application by taking the details like username, address, phone number, email along with password and confirm password (should be same as password).Ensure that the password is of 8 characters with only numbers and alphabets. Take such details for 5 users and display the details. In place of password display “****”. (Use Structures).

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main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

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main() { if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

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int a=1; printf("%d %d %d",a++,a++,a); need o/p in 'c' and what explanation too

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find simple interest & compund interest

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