Answer / susie

Answer :

(blank space)

irl

rl

l

Explanation:

Here a string (a pointer to char) is initialized with a
value “girl”. The strlen function returns the length of the
string, thus n has a value 4. The next statement assigns
value at the nth location (‘\0’) to the first location. Now
the string becomes “\0irl” . Now the printf statement prints
the string after each iteration it increments it starting
position. Loop starts from 0 to 4. The first time x[0] =
‘\0’ hence it prints nothing and pointer value is
incremented. The second time it prints from x[1] i.e “irl”
and the third time it prints “rl” and the last time it
prints “l” and the loop terminates.

Answer / arhant jain

Segmentation fault

String copy logic in one line.

11 Answers   Microsoft, NetApp,

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main(){ int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); }

1 Answers   TCS,

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can you use proc sql to manpulate a data set or would u prefer to use proc report ? if so why ? make up an example and explain in detail

0 Answers   TCS,

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

3 Answers  

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What are segment and offset addresses?

2 Answers   Infosys,

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main() { int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("\n %d", i); } a. Runtime error. b. 100 c. Some Integer not 100 d. None of the above

2 Answers   HCL, LG,

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main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

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main() { printf("%x",-1<<4); }

3 Answers   HCL, Sokrati, Zoho,

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how can i cast a char type array to an int type array

2 Answers  

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main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }

1 Answers  

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main() { unsigned int i=10; while(i-->=0) printf("%u ",i); }

2 Answers   HP,

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main() { char *p="GOOD"; char a[ ]="GOOD"; printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d", sizeof(p), sizeof(*p), strlen(p)); printf("\n sizeof(a) = %d, strlen(a) = %d", sizeof(a), strlen(a)); }

1 Answers  

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