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main()
{
char string[]="Hello World";
display(string);
}
void display(char *string)
{
printf("%s",string);
}
- 2 Answers
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Answer / susie
Answer :
Compiler Error : Type mismatch in redeclaration of
function display
Explanation :
In third line, when the function display is
encountered, the compiler doesn't know anything about the
function display. It assumes the arguments and return types
to be integers, (which is the default type). When it sees
the actual function display, the arguments and type
contradicts with what it has assumed previously. Hence a
compile time error occurs.
| Is This Answer Correct ? | 21 Yes | 3 No |
Answer / pratibha
this problem of type mismatching can be solved by declaring display function as a first line inside main() so that compiler will know that display is of type void and then it will resolve type mismatch while encountering calling function of display.
| Is This Answer Correct ? | 0 Yes | 0 No |
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C Code 
