why nlogn is the lower limit of any sort algorithm?
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print a semicolon using Cprogram without using a semicolon any where in the C code in ur program!!
35 Answers Tata Elxsi, TCS, VI eTrans,
In the following pgm add a stmt in the function fun such that the address of 'a' gets stored in 'j'. main(){ int * j; void fun(int **); fun(&j); } void fun(int **k) { int a =0; /* add a stmt here*/ }
#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }
Write a Program that Inputs 10 Numbers in an Array and Show the Maximum Number
main() { extern i; printf("%d\n",i); { int i=20; printf("%d\n",i); } }
There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }
write a program for area of circumference of shapes
main() { char not; not=!2; printf("%d",not); }
void main() { int *i = 0x400; // i points to the address 400 *i = 0; // set the value of memory location pointed by i; }
Is the following code legal? struct a { int x; struct a b; }
int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }
main() { int *j; { int i=10; j=&i; } printf("%d",*j); }