At the Party:
1. There were 9 men and children.
2. There were 2 more women than children.
3. The number of different man-woman couples possible was
24. Note that if there were 7 men and 5 women, then there
would have been 35 man-woman couples possible.
Also, of the three groups - men, women and children - at the
party:
4. There were 4 of one group.
5. There were 6 of one group.
6. There were 8 of one group.
Exactly one of the above 6 statements is false.
Can you tell which one is false? Also, how many men, women
and children are there at the party?
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Answer / guest
Statement (4) is false. There are 3 men, 8 women and 6
children.
Assume that Statements (4), (5) and (6) are all true. Then,
Statement (1) is false. But then Statement (2) and (3) both
can not be true. Thus, contradictory to the fact that
exactly one statement is false.
So Statement (4) or Statement (5) or Statement (6) is false.
Also, Statements (1), (2) and (3) all are true.
From (1) and (2), there are 11 men and women. Then from (3),
there are 2 possible cases - either there are 8 men and 3
women or there are 3 men and 8 women.
If there are 8 men and 3 women, then there is 1 child. Then
Statements (4) and (5) both are false, which is not possible.
Hence, there are 3 men, 8 women and 6 children. Statement
(4) is false.
| Is This Answer Correct ? | 6 Yes | 1 No |
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