Answer / guest

12 earrings

Assume that there are R rings, P pins and E pair of ear-
rings.

It is given that, he has 2 1/2 times as many rings as pins.
R = (5/2) * P or P = (2*R)/5

And, the number of pairs of earrings is 4 less than the
number of rings.
E = R - 4 or R = E + 4

Also, there are total 26 pieces.
R + P + 2*E = 26
R + (2*R)/5 + 2*E = 26
5*R + 2*R + 10*E = 130
7*R + 10*E = 130
7*(E + 4) + 10*E = 130
7*E + 28 + 10*E = 130
17*E = 102
E = 6

Hence, there are 6 pairs of Ear-rings i.e. total 12 Ear-
rings

Answer / durgesh tiwari

lets rings r x, pins r y and total earing pairs r z.
now,
x = 5/2y.............(1)
Again,
z= x-4.........(2)(z is the no .of pairs)
from 1 and 2
x+y+2z=26
x+2/5x+2(x-4)=26
solving this we have
x=10, putting this into 2 we have z=6 but the total no. of ear rings are 2*6=12
and pins r 4 in numbers.
TOTAL EARRINGS ARE 12 IN NUMBERS.

Answer / mss.roy222

1

Answer / priyanka

8 earings

Answer / priyanka

8 earings

(9^-2)*81*(5/6)

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