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Find the smallest number which when divided by 5,6,8 leaves
remainder 2?
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Answer / mahesh kumar
find the LCM of 5,6,8
5*3*8 = 120
Given 120 + remainder 2
120 + 2 =122
if 120/5,6, and 8,
the remainder will get
2.
| Is This Answer Correct ? | 37 Yes | 2 No |
Answer / heyyrashmi
lcm of 5,6,8 is 120, So to get remainder 2 we must add 2 in
120. So the answer will be 122...
| Is This Answer Correct ? | 16 Yes | 3 No |
Answer / angha bhangale
solution. l.c.m. of 5, 6, 8 =2x5x3x4=120
As it is the smallest number we will add a sum of
2 because it is the remainder which we want when it is
divided by 5, 6, and 8 to the l.c.m. of 5, 6, 8
= 2+120
=122
therefore the smallest number that divides 45, 6, and 8 is
122 leaving remainder 2.
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / pradeep
242.
5*6*8 = 240
240+2 =242
If the numbers are 10,12,16 then as the numbers have common
divisor 2,dive by 2 and follow the above process.
If the numbers have common divisor then divide and continue
with multiplication and addition remainder.
| Is This Answer Correct ? | 10 Yes | 21 No |
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