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In a certain department store, which has four sizes of a
specific shirt, there are 1/3 as many small shirts as medium
shirts, and 1/2 as many large shirts as small shirts. If
there are as many x-large shirts as large shirts, what
percent of the shirts in the store are medium?
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Answer / bigdummy
Given:
S = M/3
L = S/2
XL = L
Change given expressions in terms of M:
S = M/3
L = S/2 = (M/3)/2 = M/6
XL = L = M/6
Total = S + M + L + XL
so
Total = (M/3) + M + (M/6) + (M/6)
6*Total = 2M + 6M + M + M = 10M
M = (6*Total)/10 = .6 (or 60%)
| Is This Answer Correct ? | 32 Yes | 1 No |
Answer / nishant
take C in replace of B in the answer given by Sid
ans. 60%
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / sid
no of small(S) shirts= D
no of med(M) shirts= C
no of lar(L) shirts= B
no of x-lar(XL) shirts= A;
1/3 C = D;
1/2 D = B;
B=A;
% of med shirts= B/(A+B+C+D)*100= B/(B + B + 6B+ 2B)*100=
B/10B*100= 10%.
| Is This Answer Correct ? | 1 Yes | 7 No |
Answer / priii
as there is 1/3 small/medium shirts and 1/2 large/small
shirts so 20%of shirt are medium size shirt .
1/3+1/2=1/5
| Is This Answer Correct ? | 0 Yes | 7 No |
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