A+B+C+D=D+E+F+G=G+H+I=17 where each letter represent a
number from1 to 9. Find out what does letter D and G
represent if letter A=4.
- 8 Answers
- 32723 Views
- Accenture, Cognizant, Elico, TCS, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / manjeet singh
d = 5 & g = 1
Step 1.
a + b + c + d = d + e + f + g = g + h + i = 17
Means, ( a + b + c + d )+ (d +e + f + g )+ (g +h + i ) = 17 +17+17 = 17 x 3 = 51
a + b + c + d + e + f + g + h + i +( d + g ) = 51
Step 2.
But 'a' to ' i ' takes values only from 1 to 9
So a + b + c + d + e + f + g + h + i = sum of the numbers from 1 to 9 = 45
Step 3.
From step 1 and step 2
d + g = 51 - 45 = 6
possible values of d & g are (1, 5), ( 5,1 ), (2,4) & (4, 2 )
( 2, 4 ) & ( 4 , 2 ) are not possible as "a = 4 "
We have to try with other values (1, 5 ) & ( 5 , 1 )
Step 4.
When d = 1 and g = 5
1. a + b + c + d = 4 + b +c + 1 = 17
b + c = 12 ; only possible values of b & c are ( 9, 3 ) or ( 3, 9 )
2. d + e + f + g = 1 + e + f + 5 = 17
e + f = 17 - 6 = 11
possible combinations for 11 are ( 2,9 ) ; ( 3,8 ) ; (4,7 ) & ( 5,6 )
Out of the above four combinations nothing is possible beacuse
b & c takes values 3 & 9 g = 5 (assumed) and a = 4 (given).
So, d = 1 & g = 5 is not the solution.
Case 2.
When d = 5 and g = 1
1. a + b + c + d = 4 + b + c + 5 = 17
b + c = 17 - 9 = 8
only possible combination is 2 & 6
a + b + c + d = 4 + ( 2 + 6 ) + 5 = 17
2. d + e + f + g = 5 + e + f + 1 = 17
e + f = 17 - 6 = 11
The only possible value is 3 & 8
d + e + f + g = 5 + ( 3 + 8 ) + 1 = 17
g + h + i = 1 + h + i = 17
h + i = 17 - 1 = 16
The only possible value for h & i are 7 & 9
g + ( h+ i ) = 1 + ( 7 + 9 ) + 17
So the values of d = 5 & g = 1
| Is This Answer Correct ? | 131 Yes | 3 No |
Answer / sai
GIVEN A+B+C+D=D+E+F+G=G+H+I=17
A+B+C+D=17
4+2+6+5=17
D=5
D+E+F+G=17
5+3+8+1=17
G=1
G+H+I=17
1+9+7=17
D=5;G=1
| Is This Answer Correct ? | 31 Yes | 15 No |
Answer / virender singh
d = 5 & g = 1
Step 1.
a + b + c + d = d + e + f + g = g + h + i = 17
Means, ( a + b + c + d )+ (d +e + f + g )+ (g +h + i ) = 17
+17+17 = 17 x 3 = 51
a + b + c + d + e + f + g + h + i +( d + g ) = 51
Step 2.
But 'a' to ' i ' takes values only from 1 to 9
So a + b + c + d + e + f + g + h + i = sum of the numbers
from 1 to 9 = 45
Step 3.
From step 1 and step 2
d + g = 51 - 45 = 6
possible values of d & g are (1, 5), ( 5,1 ), (2,4) & (4,
2 )
( 2, 4 ) & ( 4 , 2 ) are not possible as "a = 4 "
We have to try with other values (1, 5 ) & ( 5 , 1 )
Step 4.
When d = 1 and g = 5
1. a + b + c + d = 4 + b +c + 1 = 17
b + c = 12 ; only possible values of b & c are (
9, 3 ) or ( 3, 9 )
2. d + e + f + g = 1 + e + f + 5 = 17
e + f = 17 - 6 = 11
possible combinations for 11 are ( 2,9 ) ; ( 3,8 ) ;
(4,7 ) & ( 5,6 )
Out of the above four combinations nothing is possible
beacuse
b & c takes values 3 & 9 g = 5 (assumed) and a = 4
(given).
So, d = 1 & g = 5 is not the solution.
Case 2.
When d = 5 and g = 1
1. a + b + c + d = 4 + b + c + 5 = 17
b + c = 17 - 9 = 8
only possible combination is 2 & 6
a + b + c + d = 4 + ( 2 + 6 ) + 5 = 17
2. d + e + f + g = 5 + e + f + 1 = 17
e + f = 17 - 6 = 11
The only possible value is 3 & 8
d + e + f + g = 5 + ( 3 + 8 ) + 1 = 17
g + h + i = 1 + h + i = 17
h + i = 17 - 1 = 16
The only possible value for h & i are 7 & 9
g + ( h+ i ) = 1 + ( 7 + 9 ) + 17
So the values of d = 5 & g = 1
| Is This Answer Correct ? | 11 Yes | 2 No |
Answer / puja kumari gupta
A+b+c+d=d+e+f+g=g+h+i=17, if a=4, find values of 'd' & 'g'.
all values range in between 1 to 9?
The Ans For This Question Should be:
a+b+c+d+d+e+f+g+g+h+i= 51,
a+b+c+d+e+f+g+h+i=45,
=> d + g = 6. d ≠ g => d, g, ≠ 3. a = 4 => d, g ≠ 4, 2.
=> a, d = 1, 5; or 5, 1.
Now h+i = 16 or 12; h+i = 16 => h, i = 7, 9; h+i = 12
=> h, i = 3, 9 => h or i = 9;
Also e + f = 11 => e + f = 2+9 or 3+8; But e, f ≠ 9
=> e, f = 3, 8.
b+c+d = 13, d, g = 1, 5. b, c = 2, 3, 6, 7.
h, i = 9 and either 3 or 7.
=> b, c = 2, 6 => d = 5 and g = 1.
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / abi
JUST BY TRIAL AND ERROR METHOD :
PUT
A=4
B=2
C=6
D=5
E=3
F=8
G=1
H=9
I=7
A+B+C+D=17
4+2+6+5=17
D+E+F+G=17
5+3+8+1=17
G+H+I=17
1+9+7=17
HENCE,
D=5
G=1
| Is This Answer Correct ? | 3 Yes | 11 No |
Answer / jamuna rani
here D=1 and G=5
where GIVEN A=4
A + B + C + D =D + E + F + G = G + H + I = 17
4 3 2 1 1 7 6 5 5 9 8
| Is This Answer Correct ? | 8 Yes | 43 No |
The difference between two numbers is 1365. When you divide the larger number with the smaller number the quotient is 6 and remainder is 15. What is the smaller number?
the squre of 225?
Can you tender a one rupee note in such a manner that there shall be total 50 coins but none of them would be 2 paise coins.?
I want to view the solved model papers from SBI bank.plz email to e at pehchaan10@gmail.com at the earliest
APPSC Group-2 Previous Exam Papers
A 6 inch length cylindrical through hole is drilled through the center of sphere, what will be the remaining volume of sphere ? In this question only one data is given ie., hole length - 6". In the question there is no mistake. Find the answer.
A building with height D shadow upto G. What is the height of a neighbouring building with a shadow of C
My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed. a) 6:00 am b) 6:40am c)7:40 d)7:00 e)8:00
A long thin strip of width 7cm is kept on a flat surface. Another identical strip is kept on it in an overlapping manner such that the combined width of the two is 11 cm. What is the width of 55 such strips kept like this?
"Command" opposite?
33 1/3 of 101 + 296 is
If any body has Aptitude Q & papers related to banks exam plz do email me at sagarvyas77@rediff.com
English 
