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A traveler walks a certain distance. Had he gone half a
kilometer an hour faster , he would have walked it in 4/5
of the time, and had he gone half a Kilometer an hour
slower, he would have walked 2 ½ hr longer. What is the
distance?
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Answer / guest
let d be distance and x be speed and t be time.
hence ,
d / (x+1/2) = 4/5 * t
and d / (x-1/2) = 5/2 + t
solving we get d = 15.
| Is This Answer Correct ? | 36 Yes | 10 No |
Answer / shyam
let distance=x , time=t & speed=s &v knw x=s*t .... (1)
1st case x=(s+.5)(4t/5) ..... (2)
2nd case x=(s-.5)(t+ 5/2) ..... (3)
(1) divided by (2) v get speed s = 2
similarly (2) divided by (3) v get time t = 15/2
therefore x = s * t = 2 * 15/2 = 15 km
| Is This Answer Correct ? | 25 Yes | 5 No |
Answer / naveen yadav
let d be distance and x be speed and t be time.
hence ,
d / (x+1/2) = 4/5 * t
and d / (x-1/2) = 5/2 + t
solving we get d = 15.
| Is This Answer Correct ? | 7 Yes | 4 No |
Answer / guggilam raghuram
d/(x+1/2)=4/5*t
d/(x-1/2)=5/2+t
then d=15
| Is This Answer Correct ? | 0 Yes | 0 No |
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