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There is a leak in the bottom of a cistern. When the cistern
is thoroughly repaired, it would be filled in 3 ? hours. It
now takes half an hour longer. If the cistern is full, how
long will the leak take to empty the cistern?
(a) 24 hours
(b) 28 hours
(c) 21 hours
(d) 27 hours
(e) None of these
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Answer / mohit
suppose the capacity of cistern is 30unit. when it id repaired
then takes 3 hrs.thus water coming in i hrs=10unit.
now leak tank takes 3 hrs and 1/2 hrs extra. that is, in
general think that the water filling in 1/2 hrs is equal to
the leakage of hole in 3.5 hrs.
leakage in 3.5 hrs is =10/2=5 unit
so 5 unit is leakad in =3.5 hrs
so 30unit(full capacity) is leaked in =3.5*30/5
=21 hrs
so it will take 21 hrs to empty the full cistern.
| Is This Answer Correct ? | 25 Yes | 16 No |
Answer / godwin justin
Let's assume the tank has 12 litres capacity. The pipe can fill in 3 hours therefore efficiency= 12/3=4. Now the leak caused the tank to be filled in 3 1/2 hrs.
Total capacity/efficiency of pipe-efficiency of leak=time taken
ie,12/4-x=7/2
X=(28-24)/7= 4/7 which is the efficiency of d leak.
So time take by the leak to empty the tank is:
12÷ 4/7 12*7/4= 7*3 = 21 hours
| Is This Answer Correct ? | 5 Yes | 4 No |
Answer / sagarkumar doltade
LCM of repaired tank and leak tank time=3*3.5=10.5 difference between efficiency is 1/2 then 10.5/1/2=21
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / vidhya
usual time 4(half an hour longer) -->x
ue to leak 3.5-->y
formula =x*y/x-y=>4*3.5/0.5=28 hours
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / pradeep
the amount of work done by the leak in one hour is
(2/7)-(1/4)=1/28....
Therefore the amount required to empty the whole tank is 28
hours
| Is This Answer Correct ? | 6 Yes | 9 No |
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