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A car covers a certain distance taking 7 hours in forward
journey. During the return journey, speed was increased by
12 kmph and it takes 5 hours. What is total distance covered?
(a) 210 km
(b) 70 km
(c) 440 km
(d) 220 km
(e) None of these
- 8 Answers
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Answer / santhya
let the speed of the car be xkm/h during the up journey...
total distance travelled ill remain same ,ie
7*x=(x+12)*5
or,x=30 km/hr
so distance travld= 7*30=210;
| Is This Answer Correct ? | 13 Yes | 1 No |
Answer / sankar adhikari
Let the speed is X km per hour
so total journey = 7 x X = 7X
so 7X = 5(X+12)
7X - 5X = 60
X = 30
So, Total journey = 7 x 30 = 210 k.
30 x 7 = 210 k.
(30+12) = 42 x 5 = 210 km.
| Is This Answer Correct ? | 13 Yes | 1 No |
Answer / prethvi
difference between time is (7-5)=2
12*7*5/2=210
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / suchi teegala
speed = distance / time
let the distance be x
during forward journey ,
time is given as 7hrs
and let the speed be y
therefore , y=x/7
during return journey
since the distance travelled is same in both directions
, here also we will consider the distance as x
now the speed is increased by 12kmph so the speed is y+12
now the time taken is 5 hrs
therefore , y+12=x/5
on solving the both equations
x=7y and
5y+60=x
we get x as 210 km
total distance - distance in forward journey + distance in
return journey
=x+x=2x
i.e., =210+210
=420 km is the answer
| Is This Answer Correct ? | 10 Yes | 7 No |
Answer / kritika
let the speed of the car was xkm/h during the up journey...
total distance travelled vl remain same ,ie
7*x=(x+12)*5
or,x=30 km/hr
so distance travld= 2*7*30=420;
| Is This Answer Correct ? | 4 Yes | 7 No |
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