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How do you declare A pointer to a function which receives nothing and returns nothing
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0 Answers Agilent, ZS Associates,
1)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea += sizeof(int); } return 0; } 2)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea ++; } return 0; } The output of this two programs will be different why?
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