Answer / rohit sah

Interrupt handlers as member functions _are_ possible. But they must be static member functions. Static member functions don't make use of the implicit 'this' pointer required by normal member functions. The caller of the interrupt handler doesn't know anything about objects and 'this' pointers, so it can't pass a value of such a pointer.

What is the output of this prog. ? struct A { A(){ cout << \"A\"; } }; struct B { B(){ cout << \"B\"; } }; struct C { C(){ cout << \"C\"; } }; struct D { D(){ cout << \"D\"; } }; struct E : D { E(){ cout << \"E\"; } }; struct F : A, B { C c; D d; E e; F() : B(), A(),d(),c(),e() { cout << \"F\"; } };

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