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There is a carem board where 4 No of player can play at a time but 5 No of player have to play with every for gain personal score(not double).In this case how many total minimum No of game /meach will be play..
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N=N1×N2 whole by N3
N=total minimum No of game /meach N1=No of player/team to play N2=to how many player/team to pkay.
N3=No of team/Player at once
i.e 5×4 whole by 4/=5 Ans
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