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3 small cubes have the sides 3cm, 4cm, 5cm respectively. These are melted to form a large cube. Find the ratio of total surface area of the smaller cubes to that of the larger cube.
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Answer / saurabh tyagi
volume of new cube = (3*3*3)+(4*4*4)+(5*5*5)
= 9+64+125
= 216cm3
i.e (edge)^3 = 216cm3
so, single cube= 6cm
| Is This Answer Correct ? | 21 Yes | 5 No |
Answer / ajay naykar
25:18
as total surface area of small cubes is 6 (9+16+25)=300
total surface area of new big cube= 6 (6x6)
= 216
ratio = 300:216
=25:18
| Is This Answer Correct ? | 10 Yes | 2 No |
Volume of new cube (3*3*3+4*4*4+5*5*5)=216 cubic cm
Side of new cube cube root of 216= 6cm
Therefore total surface of new cube 6*6*6=36 sq cm
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / raj
9:25
Tsa of small cube =6*3*3
Tsa of large cube = 6 *5*5
9:25
| Is This Answer Correct ? | 0 Yes | 2 No |
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