Find the least number which when divided by 7 gives the
reminder 6, when divided by 6 gives reminder 5, when divided
by 5 gives reminder 4 and so on ?
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Answer / gajanan
Lcm of 7,6,5= 210
least number= 210-1= 209
ans= 209
| Is This Answer Correct ? | 28 Yes | 9 No |
Answer / ayusha
Formula to find is : LCM(7,6,5,4,3,2,1)*n + constant = number
Here constant is 7-6 = -1
6 -5 = -1 and so constant is -1
now LCM(7,6,5,4,3,2,1)*n - 1 = number
420n -1. For any value of n this will be true. Least vale of n is 1. So minimum number is 419
| Is This Answer Correct ? | 12 Yes | 0 No |
Answer / ramya
119/7...the remainder in not 6..as 119 is divisible by 7
| Is This Answer Correct ? | 4 Yes | 9 No |
Answer / yesodhara varma
= 847
847/ x7 840 -7
847/ x6 120 -6
847/ x5 120 -5
847/ x4 120 -4
847/ x3 280 -3
847/ x2 420 -2
Find out the LCM of 7,6,5,4 = 840 and add 7 to it.
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / rndheer
Try trial and error method for the multiple numbers of 7
you will get a number 119 which should get a remainder 6 when divided by 7,5 when divided by 6,4 when divided by 5,3 when divided by 4,2 when divided by 3,1 when divided by 2,
| Is This Answer Correct ? | 6 Yes | 15 No |
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