Answer / utkarsh

/*The maximum value of the product fr a set of 3 numbers positiv or negative can be
->either the product of 2 negative numbers( the ones with highest absolut values) and 1(biggest) positive number
->or product of three biggest positive numbers
->zero if all other numbers (except that 0) ar negativ
-> product of smallest 3 negativ number if all numbers are negative
>>>
<you can try it for ANY POSSIBLE VALUES..in th array and see..>
<<<<
*/

procedure
I)
so first IF ARRAY HAS LESS THAN 3 ELEMENTS THROW ERROR
else
sort the numbers in 2 arrays..
neg[]-> with negativ values in descending order
pos[]-> with positive values in descending order
->if there is a zero set a boolean value of a variabl ISZERO as TRUE

II) IF (neg[] has zero or only 1 element) THEN

/* product of the three highest values in pos[] (ie the first three values) is the answer*/

RETURN (pos[0]*pos[1]*pos[2]);

III) ELSE IF pos[] is empty
/*(meaning there are only negative values..multiply the smallest three negative numbers (ie say -1,-2,-3,-4,-5 means multiply -1,-2,-3 you get -6)..that is the answer */


if pos[] is NULL AND if there is a zero then
RETURN ZERO;
else //if pos[] is null and no element is zero then
RETURN neg[neg.length-1]*neg[neg.length-2]*neg[neg.length-3]

/*
//NOTE:

there are only negative values and zeros
highest value is 0
check that too from ISZERO variabl..
*/

IV)ONLY if neg[] array has more than 1 value THEN
multiply th biggest 2 negativ absolute numbers


/*
//(eg {-9,-7,-6,-5 } means...tak -9 and -7..so product is 63)

V) multiply th above result with th highest postiv value from positive array...(ie pos[])

VI) compare this value got in STEP FIVE with product of the three highest values in pos[](ie product of first three values) which ever is greate is the answer
ie
*/

IF (neg[0]*neg[1]*pos[0])>(pos[0]*pos[1]*pos[2]) THEN
RETURN (neg[0]*neg[1]*pos[0])
ELSE RETURN (pos[0]*pos[1]*pos[2])


IT IS VERY EASY TO CODE THIS BECAUSE THE STEPS ARE ALMOST IN PSUEDOCODE....hope it helps...

Answer / sathish

Just count the number of -ve symbols in the array before sorting.

CODE:
void main()
{
clrscr();
int i,j,count=0,a[5]={10,2,-7,-5,3};
for(i=0;i<5;i++)
if(a[i]<0)
count=count+1;
if((count%2)==0)
{
for(i=0;i<5;i++)
{

if(a[i]<0)
a[i]=-a[i];
}
}
for(i=0;i<5;i++)
{
for(j=i;j<5;j++)
{
if(a[i]<a[j])
{
int temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
int mul=1;
for(i=0;i<3;i++)
{
mul=mul*a[i];
}
cout<<mul;
getch();
}

Answer / srikanthgowda

#include<iostream>
#include<stdlib.h>
using namespace std;

int main()
{
int i,j,a[100];
cout<<"Enter the size of array"<<endl;
int n;
cin>>n;


if(n==0)
{
cout<<"invaild!!"<<endl;
exit(1);
}

cout<<"Enter the element for array"<<endl;
for ( i=0;i<n;i++)
cin>>a[i];


int lr=0;
if(n==1)
{
cout<<"only one array is present!!"<<a[0]<<endl;
exit(0);
}
else if(n==2)
{
if(a[0]<a[1])
{
cout<<a[1]<<"largest number";
exit(0);
}

else
{
cout<<a[0]<<"largestn number";
exit(0);
}
}
else if(n==3)
{
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
if(a[i]*a[j]>lr)
{
lr=a[i]*a[j];

}
}
}

cout<<"max product="<<lr<<endl;
}



else
{
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
for(int k=j+1;k<n;k++)
{
if(a[i]*a[j]*a[k]>lr)
{
lr=a[i]*a[j]*a[k];

}
}
}
}

cout<<"max product="<<lr<<endl;
}
return 0 ;
}


/* Ouput

1.

Enter the size of array
5
Enter the element for array
9
5
1
2
3
max product=135

2.

srikanth@srikanth-System-Product-Name:~/c++$ ./a.out
Enter the size of array
5
Enter the element for array
-5
3
1
2
4
max product=24
srikanth@srikanth-System-Product-Name:~/c++$

*/

Answer / utkarsh

IF ARRAY HAS LESS THAN 3 ELEMENTS
{
THROW ERROR
}

ELSE
{
sort the numbers in 2 arrays..
neg[]-> with negativ values in descending order
pos[]-> with positive values in descending order
->if there is a zero THEN
set a boolean value of a variabl ISZERO as TRUE
}


IF pos[] is empty
{
IF ISZERO==true THEN
// if there are only negativ values and a zero
RETURN ZERO;

ELSE
// all elements are -ve and no element is zero then
RETURN (neg[neg.length-1]*neg[neg.length-2]*neg[neg.length-3]);

}

IF (neg[] has zero or only 1 element) THEN
{
RETURN (pos[0]*pos[1]*pos[2]);
}
ELSE IF neg[] array has more than 1 value THEN
{
IF (neg[0]*neg[1]*pos[0]) > (pos[0]*pos[1]*pos[2]) THEN
RETURN (neg[0]*neg[1]*pos[0]);
ELSE
RETURN (pos[0]*pos[1]*pos[2]);

}


FOR DETAILS ABT LOGIC READ ABOVE POST

Answer / jack

#include"stdafx.h"
#include<iostream>


using namespace std;
void sort(int[],int );
int maxproduct(int ar[],int n);
int main()
{
int arr[]={2,7,9,5,3,6,-12};

cout<<maxproduct(arr,7);
system("calc");


system("pause");
return 0;
}
void sort(int array1[],int n)
{
for(int i=1;i<n;i++)
for(int r=0;r<n-1;r++)

if(array1[r]>array1[r+1])
{
int temp=array1[r];
array1[r]=array1[r+1];
array1[r+1]=temp;
}

}
int maxproduct(int ar[],int n)
{
sort(ar,n);
int max=1;
for(int i=n-1;i>=n-3;i--)
max*=ar[i];
return max;
}

Answer / bharghavi

consider the array: 10,2,-7,-5,3
Descending order: 10,3,2,-5,-7
Then ur result will give: 10*3*2=60
But the max. product can be: 10*(-5)*(-7) =350

Answer / sathish

1)Sort the array in descending order.
2)Multiply for required number of indices.

CODE:

int mul=1;
for(i=0;i<3;i++)
{
mul=mul*a[i];
}
cout<<mul;

output for printf("printf");

0 Answers  

Write a C/C++ program that connects to a MySQL server and checks if the InnoDB plug-in is installed on it. If so, your program should print the total number of disk writes by MySQL.

0 Answers  

write a function -oriented program that generates the Fibonacci, the current numbers of n(as input) and display them (series). In Fibonacci, the current third number is the sum of the previous number.

3 Answers  

Write a C++ program without using any loop (if, for, while etc) to print prime numbers from 1 to 100 and 100 to 1 (Do not use 200 print statements!!!)

0 Answers   iGate,

create a stucture student containing field for roll no,class,year and marks.create 10 student annd store them in a file

0 Answers   HCL,

write a program using virtual function to find the transposing of a square matrix?

0 Answers  

Code for Method of Handling Factorials of Any Size?

0 Answers  

We need to write the function to check the password entered is correct or not based on the following conditions.. a) It must have atleast one lower case character and one digit. b)It must not have any Upper case characters and any special characters c) length should be b/w 5-12. d) It should not have any same immediate patterns like abcanan1 : not acceptable coz of an an pattern abc11se: not acceptable, coz of pattern 11 123sd123 : acceptable, as not immediate pattern adfasdsdf : not acceptable, as no digits Aasdfasd12: not acceptable, as have uppercase character

0 Answers  

Code for Easily Using Hash Table?

0 Answers  

hello friends, given an expression we have to remove the unwanted brackets in that expression. Eg : (a+b) ---> a+b (a+b)*(c)-----> (a+b)*c. Please mail me if you know the logic. My mail id is : saravana6m@gmail.com. Thank you in advance :-)

1 Answers   GrapeCity, Microsoft,

how to write a program that opens a file and display in reverse order?

0 Answers   SMC,

write a program that prompt the user to enter his height and weight,then calculate the body mass index and show the algorithm used

0 Answers   Jomo Kenyatta University,