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16) There are two water tanks A and B, A is much smaller
than B. While water fills at the rate of one litre every
hour in A, it gets filled up like 10, 20, 40, 80, 160... in
tank B. (At the end of first hour, B has 10 litres , second
hour it has 20, and so on). If tank B is 1/32 filled after
21 hours, what is the total duration required to fill it
completely?
a) 26 hrs b) 25 hrs c) 5 hrs d) 27 hrs

Question Posted / navneet

Answers were Sorted based on User's Feedback



16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / sumit kumar

10+20+40+80+160....
10(1+2+4+8+16..............)
this is a gp
first term=a
ratio=2
t21=1*2^20
given*******

1/32 of x=2^20
x=2^25
therefore in gp
Tn=ar^n-1
n-1=25
n=26
=26

Is This Answer Correct ?    141 Yes 16 No

16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / sushma baradwaj

1 of the 32 parts is filled in 21 hrs...
as the level gets double per every hour..
1....1*2..2*2(4)...4*2(16)..16*2(32)
so it will take 5 more hours to fill d tank completly
hence 21+5 = 26

Is This Answer Correct ?    79 Yes 12 No

16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / rajesh

shortcut to this kind of somes just find how many 2's r there in the 32 prime factor u will get 5
just add this 5 to the 21hours (21+5=26)
so ans is 26

Is This Answer Correct ?    39 Yes 8 No

16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / saurabh singh

Solution: for every hour water in tank in B is doubled,

Let the duration to fill the tank B is x hours.

x/32 part of water in tank of B is filled in 21 hours,

Next hour it is doubled so,

2*(x/32) part i.e (x/16) part is filled in 22 hours,

Similarly (x/8)th part in 23 hours,(x/4)th part is filled in
24 hours,
(x/2)th part is filled in 25 hours, (x)th part is filled in
26 hours

So answer is 26 hours.

Is This Answer Correct ?    22 Yes 1 No

16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / sherley

Given that B fills up at the rate 10, 20, 40 etc...
This is a geometric progression where a = 10 r = 2
so after 21 hrs liters in B = a*r21 = 10 * 221
This is equal to 1/32 volume of B
SO TOTAL VOLUME OF B = 32 * 10 * 221 which is =10 * 226
So hrs required to fill up B is 26

Is This Answer Correct ?    4 Yes 0 No

16) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of o..

Answer / siddarth

The given fraction part is 1/32 or (1/2^5)
as given series is 10(1,2,4,8,16...)or 10(2^0,2^1,2^2,2^3,2^4,2^5..) in the series we got 2^5 as after 5 hours.
so after 21 hours from 5 hours i.e 21+5=26 (ans=26)

Is This Answer Correct ?    2 Yes 0 No

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