Interested to Buy Any Domain ? << Click Here >> for more details...
We measure the performance of a telephone line (4 KHz of
bandwidth). When the signal is 20 V, the noise is 6 mV.
What is the maximum data rate supported by this telephone
line?
- 3 Answers
- 24175 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / zeeshan ali hirani
Capacity=B*log2(1+SNR)=
4000 * (log(1 + (20 / 0.006)) / log(2)) = 46 812.7305 bps
| Is This Answer Correct ? | 76 Yes | 18 No |
Answer / shikamaru
Ans 4,000 log2 (1 + 10 / 0.005) = 43,866 bps
| Is This Answer Correct ? | 22 Yes | 8 No |
Answer / vikas chauhan
snr = sig power/noise power
snr = 20Vsq / 6mVsq
and use the formula
| Is This Answer Correct ? | 4 Yes | 0 No |
how to hide control panel?in my pc?
2 Answers Infotech, TCS, Wipro,
When a customer starts abusing u how will u deal with him? n what do u do?
How to send XAML file on server using HTTP protocol?
What is ftp used for?
How does FDDI node determine whether it can send asynchronous traffic and synchronous traffic
what are the service primitives present in cn?
What?s a VLAN?
what is the concept of subnetting and why its used and where it is used?
Explain Protocols?
pls tell me briefly about APIPA
Draw diagrams for the waveforms you would expect when the bit sequence 10111001 is transmitted on IEEE 802.3
How do all the layers communicate with each other?
SNMP 
