suppose you build a tower interlocking cubes that is 99
cubes high. And suppose you have to paint each square on
the tower. How many squares would you have to paint?
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Answer / kiran
its 396.. 99*4 + 1 =397. Because top most cube will have 5
faces to be painted.
| Is This Answer Correct ? | 53 Yes | 2 No |
Answer / asaranprasad
397...
topmost cube needs 5 sides painting
rest 98 cubes need oly 4 side painting
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / narsee
Actually my previous answer needs some right calculation
its not 395 ..... its 397
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / pradeepanandh
the top cube has 5 squares to b painted and remaining 98
cubes have 4 sides to paint..
so
98*4=392
then top cube have 5 sides to b painted
hence
392+5=397
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / abdul
the top cube has 5 squares to be painted and the remaining
98 cubes have 4 sides to paint.
so you multiply 98*4=392 .
THEN THE TOP OF THE CUBE HAS 5 SIDES TO BE
PAINTED .392+5=397
answer is 397
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / narsee
(99*6)-(98*2)-1 = 395
because,
Total squares 594
out of 594, 197 (2 squares from bottom 98 cubes and bottom
square of the top cube) can be left.
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / b subrahmanyam
They are to be 4 cubes high.because a cube contains four side so 99.....99*4=396
cube multiplied by 4
| Is This Answer Correct ? | 1 Yes | 4 No |
Answer / arun
its 396.. 99*4=396. because a cube contains four side so 99
cube multiplied by 4
| Is This Answer Correct ? | 12 Yes | 18 No |
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