main(){ char a[100]; a[0]='a';a[1]]='b';a[2]='c';a[4]='d'; abc(a); } abc(char a[]){ a++; printf("%c",*a); a++; printf("%c",*a); }

2 Answers  

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Sorting entire link list using selection sort and insertion sort and calculating their time complexity

1 Answers   Infosys, Microsoft, NetApp,

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main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcpy(a,b)); } a. “Hello” b. “Hello World” c. “HelloWorld” d. None of the above

4 Answers   Corporate Society, HCL,

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How do you create a really large matrix (i.e. 3500x3500) in C without having the program crash? I can only reach up to 2500. It must have something to do with lack of memory. Please help!

1 Answers  

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main() { int i=1; while (i<=5) { printf("%d",i); if (i>2) goto here; i++; } } fun() { here: printf("PP"); }

1 Answers  

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main() { int x=5; for(;x!=0;x--) { printf("x=%d\n", x--); } } a. 5, 4, 3, 2,1 b. 4, 3, 2, 1, 0 c. 5, 3, 1 d. none of the above

2 Answers   HCL,

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Given an array of size N in which every number is between 1 and N, determine if there are any duplicates in it. You are allowed to destroy the array if you like.

21 Answers   ABC, eBay, Goldman Sachs, Google, HUP, Microsoft, TATA,

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void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %d\n",++i); }

3 Answers  

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#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }

1 Answers  

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main() { int i=0; while(+(+i--)!=0) i-=i++; printf("%d",i); }

9 Answers   CSC, GoDB Tech, IBM,

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You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

2 Answers   HCL,

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