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char* ptr = "Rahul";
*ptr++;
printf("%s",ptr);
What will be the output
- 9 Answers
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Answer / vadivelt
Since address pointed by ptr got incremented, ptr will point to
address of char 'a'.
So o/p will be - ahul
| Is This Answer Correct ? | 73 Yes | 5 No |
Answer / amit
Ans: ahul
Reason:
Initially character pointer ptr pointed to the first character
of Rahul..when we increase it by increament operator it increase one byte.because size of character is one bye..
now it point to a..
we print from here
therefore we got above answer
so
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / sayali
this code generates the output as,
ahul
but is also generate warning
that
code has no effect..
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / deepak
Ans:Sahul
Reason:
Intially *ptr contains ASCII value of 'R' on incrementing it
will points to ASCII value of 'S'.
| Is This Answer Correct ? | 2 Yes | 15 No |
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