Why preincrement operator is faster than postincrement?
Answers were Sorted based on User's Feedback
Answer / sanish joseph
the pre inc operator increments the value of that particular
variable on that line itself
the post inc operator increments the value of that
particular variable after going on the next line
in simple words
eg.
e=5; on this line value of e=5
e++; on this line value of e=5
++e; on this line value of e=7
Is This Answer Correct ? | 27 Yes | 9 No |
Answer / devesh patel
b/c preeincrement take one byte instruction & post
increment takes two instruction
Is This Answer Correct ? | 16 Yes | 7 No |
Answer / ranjeet garodia
Pre increment operator is use the concept of value by
reference that means it increment the actual object.
While post increment use call by value concept that is it
create the local object, operate on that, then it will
increment actual object, so takes time to create local
object
Is This Answer Correct ? | 10 Yes | 7 No |
Answer / shakti singh khinchi
Because post increment operator uses a temporary variable to
store the incremented value for a variable until it is used
in the next executed statement, whereas pre increment
operator not using any temp variable, it is just increase
that value at the time of execution using reference.
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / puneet nagpal
postincrement did not increment unless it find ; so it increments after the end of statement. while the preincrement operator increment before the end of statement. so preincrement operator is faster than postincrement operator.
ex- a=10;
a++;value incremented after the end of statement but
at this point value is 10.
a++;now the value is incremented to 11.
++a; preincrement incremented within the statement now
the value is 12.
Is This Answer Correct ? | 1 Yes | 0 No |
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