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#include<stdio.h>
void main()
{
int i=1;
printf("%d%d%d",i++,++i,i);
}
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Answer / vinod
3 2 1.because the print f function print right to leftand
the compiler reads left to right.thus answer is 3 2 1
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / shruti
the answer will be:-
1,3,3
as i++ is postfix so first it will print the value then
increament..
after first increament the second preincreament comes and
the value becomes 3..
third time also it will 3..
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / aaradhana
1,2,2
since to print the postincremented value then i takes the
value 1 then gets preincremented by1 & takes i=2.To print i
value then it takes the updated value i=2.
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / ramya
Answer is 133.
first the compiler prints 'i' value and prints the value,
next it increments the 'i' value and then prints its value.
| Is This Answer Correct ? | 8 Yes | 14 No |
Answer / priyadarshan kasta
1 2 2
becoz, this line will execute frm right to left side.
that is, first i=1, then ++i will be 2 and then i++ will be
printed as 2. So , it will print as 1 2 2(i.e i++,++i,i)
| Is This Answer Correct ? | 1 Yes | 10 No |
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#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }
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