Performance Algorithm A performs 10n2 basic operations and algorithm B performs 300 lg n basic operations. For what value of n does algorithm B start to show its better performance?
7322Complexity T(n) What is the time complexity T(n) of the following portions of code? For simplicity, you may assume that n is a power of 2. That is, n = 2k for some positive integer k. a) ? for (i = 1; i <= n; i++) { j = n; cout << i << ? ? j << ? ? << endl; } b) ? for (i = 0; i <= n; i += 2) { j = n; cout << i << ? ? j << ? ? << endl; } c) ? for (i = n; i >= 1; i = i/2) { j = n; cout << i << ? ? j << ? ? << endl; } d) for (i = 1; i <= n; i++) { j = n; while (j >= 0) { cout << i << ? ? j << ? ? << endl; j = j - 2; } }
2611Complexity T(n) Write a linear-time algorithm that sorts n distinct integers, each of which is between 1 and 500. Hint: Use a 500-element array. (Linear-time means your algorithm runs in time c*n + b, where c and b are any constants that do not depend on n. For example, your algorithm can run in time n, or time 2n + 1, or time 5n + 10, or time 100n + 6, but not time c*n*n = c*n?.)
1 6427Subsets Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a list that is the input to the algorithm. (Since it is a set, you may assume all elements in the list are distinct.)
1 13128Min-Max Write an algorithm that finds both the smallest and largest numbers in a list of n numbers and calculate its complexity T(n).
1 6232Min-Max Write an algorithm that finds both the smallest and largest numbers in a list of n numbers and with complexity T(n) is at most about (1.5)n comparisons.
ABC, College School Exams Tests, ITC Infotech, Kyambogo University, Qatar University,
10 43366Faster Computers Suppose you have a computer that requires 1 minute to solve problem instances of size 1000. What instance sizes can be run in 1 minute if you buy a new computer that runs 1000 times faster than the old one, assuming the following time complexities T(n) for our algorithm? (a) T(n) = O(n). (b) T(n) = O(n3). (c) T(n) = O(10n).
1 10641Algorithm in O(2n) Presently we can solve in our hypothetical machine problem instances of size 100 in 1 minute using algorithm A, which is a O(2n). We would like to solve instances of size 200 in 1 minute using algorithm A on a new machine. What is the speed of the new machine should be?
2 6031how to use textfile for taking value for parametrization instead of datatable or global sheet
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6 14318write the function. if all the character in string B appear in string A, return true, otherwise return false.
11 15721Write a Program in Visual Basic by means of which we can send any data from Visual basic program to any other application running on that machine whether that application supports OLE or not.....
1 3218
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solve the problem in the programming language C++"if a five digit number is input through the keyboard.Write a program to calculate the sum of its digits(hint: use the modulus operator)
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find out the list of users who have access to all t-codes starts with 'SU'? thanks in advance all.
plzzzzzzzzz xplain this code import java.awt.*; import java.awt.event.*; import java.awt.MenuItem.*; import java.sql.*; import sun.jdbc.odbc.*; import java.io.*; public class ShopDelivery extends Frame implements ActionListener { Label l1,l2,l3,l4,l5,l6,l7,l8,l9,l10,l11,l12,l13; Button exit,save,next,top,prev,botm,ad,show; TextField txtCMemoNo,txtConsNo,txtCMemoDt,txtConsName,txtAddr1,txtPhNo ,txtBookDtold,txtPrintDt,txtOldCMemNo,txtOldDlryDt,adr2,adr3 ,tot,stnry,rmrk; String ConsName; String Addr1; public static void main(String sr[]) { new ShopDelivery().setVisible(true); } public ShopDelivery() { super("Shop Delivery"); Statement stmt; ResultSet rs; //PreparedStatement pst; Connection con; try { Class.forName ("sun.jdbc.odbc.JdbcOdbcDriver"); con=DriverManager.getConnection("jdbc:odbc:Agency"); if (con!=null); System.out.println ("connected"); stmt =con.createStatement (); } catch(Exception e1) { System.out.println (e1); } setSize(1280,800); setBackground(Color.CYAN); setLayout(null); l1=new Label("Cashmemo No"); l1.setBounds(260,60,90,30); l1.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l1.setAlignment(Label.CENTER); add(l1); l2=new Label("CONSMR NO"); l2.setBounds(30,60,90,30); l2.setFont(new Font("TimesRoman",Font.PLAIN,15)); l2.setAlignment(Label.CENTER); add(l2); l3=new Label("Book DATE"); l3.setBounds(520,60,90,30); l3.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l3.setAlignment(Label.CENTER); add(l3); l4=new Label("NAME"); l4.setBounds(30,150,45,30); l4.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l4.setAlignment(Label.CENTER); add(l4); l5=new Label("ADRS"); l5.setBounds(30,220,45,30); l5.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l5.setAlignment(Label.CENTER); add(l5); l6=new Label("PH NO"); l6.setBounds(500,150,45,30); l6.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l6.setAlignment(Label.CENTER); add(l6); l7=new Label("OldBkDt"); l7.setBounds(30,390,55,30); l7.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l7.setAlignment(Label.CENTER); add(l7); l8=new Label("Print Date"); l8.setBounds(320,390,65,30); l8.setFont(new Font("TimesRoman",Font.PLAIN,15)); l8.setAlignment(Label.CENTER); add(l8); l9=new Label("CMemo No"); l9.setBounds(700,390,65,30); l9.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l9.setAlignment(Label.CENTER); add(l9); l10=new Label("Del Date"); l10.setBounds(550,390,55,30); l10.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l10.setAlignment(Label.CENTER); add(l10); l13=new Label("REMARKS"); l13.setBounds (30,630,85,30); l13.setFont(new Font ("TimesRoman",Font.PLAIN,15)); l13.setAlignment (Label.CENTER); add(l13); txtCMemoNo=new TextField(); txtCMemoNo.setBounds(375,60,80,30); txtCMemoNo.setBackground(Color.white); add(txtCMemoNo); txtConsNo=new TextField(); txtConsNo.setBounds(130,60,80,30); txtConsNo.setBackground(Color.white); add(txtConsNo); txtCMemoDt=new TextField(); txtCMemoDt.setBounds(635,60,80,30); txtCMemoDt.setBackground(Color.white); add(txtCMemoDt); txtConsName=new TextField(); txtConsName.setBounds(100,150,200,30); txtConsName.setBackground(Color.white); add(txtConsName); txtAddr1=new TextField(); txtAddr1.setBounds(100,220,350,30); txtAddr1.setBackground(Color.white); add(txtAddr1); adr2=new TextField(); adr2.setBounds(100,250,350,30); adr2.setBackground(Color.white); add(adr2); adr3=new TextField(); adr3.setBounds(100,280,350,30); adr3.setBackground(Color.white); add(adr3); txtPhNo=new TextField(); txtPhNo.setBounds(570,150,150,30); txtPhNo.setBackground(Color.white); add(txtPhNo); txtBookDtold=new TextField(); txtBookDtold.setBounds(30,440,60,30); txtBookDtold.setBackground(Color.white); add(txtBookDtold); txtPrintDt=new TextField(); txtPrintDt.setBounds(320,440,60,30); txtPrintDt.setBackground(Color.white); add(txtPrintDt); txtOldCMemNo=new TextField(); txtOldCMemNo.setBounds(700,440,60,30); txtOldCMemNo.setBackground(Color.white); add(txtOldCMemNo); txtOldDlryDt=new TextField(); txtOldDlryDt.setBounds(550,440,60,30); txtOldDlryDt.setBackground(Color.white); add(txtOldDlryDt); rmrk=new TextField(); rmrk.setBounds(140,630,600,30); rmrk.setBackground(Color.white); add(rmrk); exit=new Button("EXIT"); exit.setBackground(Color.orange); exit.setBounds(760,700,40,40); exit.addActionListener(this); add(exit); save=new Button("SAVE"); save.setBackground(Color.orange); save.setBounds(715,700,40,40); save.addActionListener(this); add(save); next=new Button("NEXT"); next.setBackground(Color.orange); next.setBounds(90,700,40,40); next.addActionListener(this); add(next); top=new Button("TOP"); top.setBackground(Color.orange); top.setBounds(0,700,40,40); top.addActionListener(this); add(top); prev=new Button("PREV"); prev.setBackground(Color.orange); prev.setBounds(45,700,40,40); prev.addActionListener(this); add(prev); botm=new Button("BOTM"); botm.setBackground (Color.orange); botm.setBounds (135,700,40,40); botm.addActionListener (this); add(botm); ad=new Button("ADD"); ad.setBackground (Color.orange); ad.setBounds (300,700,40,40); ad.addActionListener (this); add(ad); show=new Button("SHOW"); show.setBackground (Color.orange); show.setBounds (345,700,40,40); show.addActionListener (this); add(show); } public void actionPerformed(ActionEvent e) { if(e.getSource()==exit) { this.dispose(); System.exit(0); } /*if(e.getSource()==save) { try { Connection con=DriverManager.getConnection("jdbc:odbc:Agency"); PreparedStatement pst=con.prepareStatement("INSERT INTO NewCon values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"); pst.setInt (1,Integer.parseInt(txtConsNo.getText())); pst.setInt (2,Integer.parseInt(txtCMemoNo.getText())); pst.setString (3,txtCMemoDt.getText()); pst.setString (4,txtConsName.getText()); pst.setInt(5,Integer.parseInt (txtPhNo.getText())); pst.setString(6,txtAddr1.getText()); pst.setString(7,adr2.getText()); pst.setString(8,adr3.getText()); pst.setInt(9,Integer.parseInt (txtBookDtold.getText())); pst.setInt(10,Integer.parseInt (txtPrintDt.getText())); pst.setInt(11,Integer.parseInt (txtOldDlryDt.getText())); pst.setInt(12,Integer.parseInt (txtCMemoNo.getText())); pst.setInt(13,Integer.parseInt (tot.getText())); pst.setInt(14,Integer.parseInt (stnry.getText())); pst.setString(15,rmrk.getText()); pst.executeUpdate (); con.close(); } catch(Exception e2) {System.out.println(e2);} //cs(txtConsName.getText (),txtAddr1.getText()); }*/ if(e.getSource()==ad) { try { txtCMemoNo.setText(""); txtCMemoDt.setText(""); txtConsName.setText(""); txtAddr1.setText(""); txtPhNo.setText(""); txtBookDtold.setText(""); txtPrintDt.setText(""); //txtCMemoNo.setText(""); txtOldDlryDt.setText(""); adr2.setText(""); adr3.setText(""); tot.setText(""); //stnry.setText(""); //rmrk.setText(""); Connection con1=DriverManager.getConnection("jdbc:odbc:Agency"); Statement stmt1=con1.createStatement(); ResultSet rs1=stmt1.executeQuery("SELECT Max(Cons_No) FROM NewCon"); int nextcono = rs1.getInt ("Cons_No"); System.out.println (nextcono); nextcono=nextcono+1; txtConsNo.setText ("nextcono"); con1.close(); } catch(Exception e4){} } } }
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A suduco given & u hv 2 check if it is incomplete(blanks left),or correct or incorrect