I have multiple jobs ( JCLs with several JOB cards ) in a
member. What happens if I submit it?
Answer Posted / anurag
It will show the JCL error , as there should be only one
job card for each job,
multiple jobs can not be kept in a single member with
multiple Job cards,
Each jobs should be placed in a different member with only
one job card,
For each Job Job card will be only one and multiple steps
could be there up to the no of 255.
| Is This Answer Correct ? | 0 Yes | 6 No |
Post New Answer View All Answers
What statement marks the beginning of a job step; assigns a name to the step; identifies the program or catalogued or in-stream procedure to be executed in the step?
Explain how can a jobs execution priority be modified?
what happens in conversion stage in job processing?
Immediate Job opening for mainframe professionals in Keane Bangalore. Please find the below details: Organization: Keane India Location: Bangalore Skill: COBOL, JCL,VSAM,DB2,CICS,IMS,REXX,CLIST Exp: 1 to 4 years only Employment Type: Permenant Employee Note: If you have attended keane interview in past 6 months please ignore this job opening. Please respond to email id keanemfjob@gmail.com OR keanemfjob@yahoo.in with your latest resume and following details, We will contact you within 24 hours: Total IT Exp: Exp in Mainframe: Current CTC: Expected CTC: Notice Period:
Are there any set of rules for the names of the steps used in a job?
How is the record format of an output dataset specified?
Explain about ISPF/TSO Commands
What is the function of the steplib dd statement?
what is JCL?
How dummy is used in jcl?
How to remove the spaces at end of each record in the output file Via COBOL program? note: The file has a VB length ----TRY
How can the disposition of sysout datasets be set for an entire jobstream?
what happens when COND is coded in JOB statement and when COND is coded inside EXEC statement?
Explain the function of dd disp parameter?
how do you create a dataset in a jcl with the same file organisation as that of another existing dataset?