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Three containers are of 15,10 and 6 ltrs capacity.
Initially its in configuration (15,0,0). Make it to
configuration (2,8,5).
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Answer Posted / md
In my understanding this is not possible.
reason:
the final state expected is below [ no is () is the
capacity of the respective container. ]
2(15) 8(10) 5(6)
None of teh container is full.
Lets try for a back calculation.
What can be the last step, so that it results 2lt 8lt and 5
lt is respective containers..
Now the prob is you wont find a answr of it.
assume the last step to achieve this ... was pouring x lt
of lequid from 1st to 2nd. so 1st had 2+x lt and 2nd had 8-x
Now how would one measure this x amount?.. Usually in such
cases measurement comes from container's capacity. Hence at
any state at least one container has to be totally full or
totally empty
see example below:
15 0 0
9 0 6 - 3rd is totally full
0 9 6 - 3rd is totally full
6 9 0 - 3rd is totally empty [when none is totally full]
5 10 0 - 2nd is totally full
0 10 5 - 2nd is totally full
I cant derive any state out of it... where all are partly
full.
Hence the solution expected is not possible to derive
without additional equipment.
| Is This Answer Correct ? | 10 Yes | 2 No |
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