How do you define a sort file in JCL that runs the COBOL
program?
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Answer Posted / shinoy sansilavose
Suppose if you want to sort a file TEST.OUTPUT.FILE which
is the output of your COBOL program then you can do the
following coding in JCL,
//SORTIN DD DSN=TEST.OUTPUT.FILE,DISP=SHR
//SORTOUT DD DSN=TEST.OUTPUT.SORT.FILE,
// DISP=(NEW,CATLG,DELETE),
// UNIT=TESTDA,
// SPACE=(CYL,(50,50)),
// DCB=(RECFM=FB,LRECL=80,BLKSIZE=0)
//SYSIN DD *
SORT FIELDS=(1,5,CH,A)
Now the sorted file TEST.OUTPUT.SORT.FILE will be sorted
based on the field starting from 1 to 5 specified in the
input for SORT.
| Is This Answer Correct ? | 30 Yes | 7 No |
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