During a trip to a wildlife safari, 29 tourists clicked
photographs of tigers, 21 clicked photos of elephants, 26
clicked photos of deer; 14 clicked photos of elephants and
deer, 12 clicked photos of tigers and elephants, 15 clicked
photos of deer and tigers, and 8 clicked photos of all the
three animals. Each tourist took at least one photograph.
1. How many tourists went to the wildlife safari?
2. How many tourists clicked photographs of tigers only?
Answer Posted / sumati
Elephants (e)=21
Tigers (t)=29
Deer (d)=26
e & d = 14
t & e = 12
d & t = 15
e & d & t = 8
no. of tourists = union of e,d,t = 21+29+26 - (14+12+15) + 8
= 76-41+8 =43
tigers only = 29 -(12+15) + 8
= 10
Is This Answer Correct ? | 13 Yes | 1 No |
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