There are two natural numbers. A cube difference of the
squares is a square difference of their cubes.These are the
smallest possible numbers. what is the sum of these numbers?
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Answer Posted / Mrigendra Singh
The smallest pair of numbers that satisfy the given condition are 2 and 3. The cube difference of their squares is (4^3 - 3^3) = 64 - 27 = 37, which is a square difference of their cubes because 37 = (5^2 - 3^2).
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