Sr-90, a radioactive isotope, is a major product of an atomic
bomb explosion. It has a half life of 28.1 year. Calculate the
first order rate constant for this nuclear decay and the
fraction of 90Sr that remains after 10 half lives?
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Answer Posted / Gurvinder Singh
First, calculate the number of half-lives passed: 10 * 28.1 years = 281 years. The remaining fraction of Sr-90 is 1/2^(number of half-lives), so in this case it's 1/2^10 ≈ 0.000977 or approximately 0.0977%. To calculate the first order rate constant, use the formula k = ln(2)/half life. For Sr-90, k = ln(2) / 28.1 years ≈ 0.0249 years^-1.
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