a dog takes 4 leaps for every 5 leaps of a hare but 3
leaps of a dog are equal to 4 leaps of the hare .compare
their speeds(.......... please give explanation....)
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Answer Posted / pritesh moure
Let 1 leap of dog= x meter
1 leap of hare= y meter
So distance covered by 3 leaps of dog & 4 leaps of hare are equal
i.e. 3x=4y, x/y =4/3........(i)
Let time taken by 4 leaps of dog be 't' which is equal to time taken by 5 leaps of hare.
So time taken to cover 1 leap
By dog= t/4
By hare= t/5
Now Speed= (Distance covered in 1 leap)/ (Time taken to cover 1 leap)
Speed of dog(S1) = x/(t/4)=4x/t
Speed of hare(S2) = y/(t/5)=5y/t
So S1/S2 =(4x/t)/(5y/t)= 4x/5y=(4×4)/(5×3)= 16/15. (x/y=4/3 by (i) )
Ans: 16/15.
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