In A,B,C are having some marbles with each of them. A has giben B and C the same number of
marbles they already have to each of them. then, B gave C and A the same no. of marbles they have,
then C gave A and B the same no. of marbles they have. At the end A,B,and C have equal no. of
marbles.
(i) If x,y,z are the marbles initially with A,B,C respectively. then the no of marbles B have at the
end
(a) 2(x-y-z) (b) 4(x-y-z) etc.
(ii)If the total no. of marbles are 72, then the no. of marbles with A at the starting
a. 20 b. 30 c. 32
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Answer Posted / manoj k l
total no of marbles=72
at the end all are having equal no of marbles i.e.,each having 24.
calculate from bottom:
A B C
39 21 12 (A gave 21 to B and 12 to C)
6 42 24 (B gave 6 to A and 12 to C)
12 12 48 ( c gave 12 to A and 12 to B)
24 24 24
| Is This Answer Correct ? | 3 Yes | 0 No |
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